It is shown using the square root symbol: {eq}\sqrt{16}=4 \: and \: -4 {/eq}. There are always two answers, the positive answer and the negative answer. The positive answer is the principal square ...
Share, comment, bookmark or report
To find the square root of 225 using these prime numbers, take one number from each set of two and multiply them together: 5 ⋅ 3 = 15. 15 is the square root of 225. The square of a square root ...
Share, comment, bookmark or report
Finding the fourth root of a number is the opposite of multiplying a number by itself 4 times. In other words, it's the opposite of using an exponent of 4. Let's look at it mathematically. x4 = 256.
Share, comment, bookmark or report
-4 has two complex square roots, namely +-2i (where i = sqrt(-1)) ... What is the square root of negative 4?
Share, comment, bookmark or report
Practice Questions for the Negative Square Root. Note: You may use i to denote the square root of -1. 1. Solve the equation 2x^2 + 200 = 0. 2. Evaluate the product (4 + 8i)(6 - 7i).
Share, comment, bookmark or report
Scott is working a problem in his algebra class where he is looking for numbers that solve polynomial equations. The first few go smoothly, but then he comes to one that has him stumped: x^2 + 4 ...
Share, comment, bookmark or report
A square root is a number that, when multiplied by itself, equals a specific number. For example, 6 is the square root of 36 because 6 × 6 = 36. A square root will be both the positive and ...
Share, comment, bookmark or report
sqrt (1/4) Using a simple observation, we got: =sqrt ( (1^2)/ (2^2)) Using the properties, (a^b)/ (c^b)= (a/c)^b. So, we got. =sqrt ( (1/2)^2) =+-1/2. Since we are talking about real numbers, we will only take the principal (positive) square root, and so the answer will be just 1/2. 1/2 We have: sqrt (1/4) Using a simple observation, we got ...
Share, comment, bookmark or report
For starters (x^2+4) > 0 for all x in RR, so it has no linear factors with real coefficients. Suppose you produced some formula f (x) for sqrt (x^2+4). Then f (1) = sqrt (5) and f (2) = sqrt (8) = 2 sqrt (2). So any such formula f (x) would involve square roots or fractional exponents or suchlike, and be as complex as the original sqrt (x^2+4)
Share, comment, bookmark or report
Answer link. 2 and -2 are square roots of 4. The principal square root of 4, (denoted sqrt4) is 2 A number is a square root of 4 is, when multiplied by itself, the result is 4. In notation: n is a square root of 4 if n^2 = n xx n = 4 There are two numbers that will work 2 xx 2 = 4 and also -2 xx -2 = 4 so the numbers 2 and -2 are square roots of 4.
Share, comment, bookmark or report
Comments